5=(p^2-p)/2

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Solution for 5=(p^2-p)/2 equation: 


p in (-oo:+oo)

5 = (p^2-p)/2 // - (p^2-p)/2

5-((p^2-p)/2) = 0

(-1*(p^2-p))/2+5 = 0

(-1*(p^2-p))/2+(2*5)/2 = 0

2*5-1*(p^2-p) = 0

p-p^2+10 = 0

p-p^2+10 = 0

p-p^2+10 = 0

DELTA = 1^2-(-1*4*10)

DELTA = 41

DELTA > 0

p = (41^(1/2)-1)/(-1*2) or p = (-41^(1/2)-1)/(-1*2)

p = (41^(1/2)-1)/(-2) or p = (41^(1/2)+1)/2

(p-((41^(1/2)-1)/(-2)))*(p-((41^(1/2)+1)/2)) = 0

((p-((41^(1/2)-1)/(-2)))*(p-((41^(1/2)+1)/2)))/2 = 0

((p-((41^(1/2)-1)/(-2)))*(p-((41^(1/2)+1)/2)))/2 = 0 // * 2

(p-((41^(1/2)-1)/(-2)))*(p-((41^(1/2)+1)/2)) = 0

( p-((41^(1/2)+1)/2) )

p-((41^(1/2)+1)/2) = 0 // + (41^(1/2)+1)/2

p = (41^(1/2)+1)/2

( p-((41^(1/2)-1)/(-2)) )

p-((41^(1/2)-1)/(-2)) = 0 // + (41^(1/2)-1)/(-2)

p = (41^(1/2)-1)/(-2)

p in { (41^(1/2)+1)/2, (41^(1/2)-1)/(-2) }

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